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  #41 (permalink)  
Old 10-06-2010, 21:50
OnTheLam's Avatar
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Ha! Well done, amzamz, very scientific! (Of course, if you are off by even a fraction . . . )
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  #42 (permalink)  
Old 11-06-2010, 00:39
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Full name: Matt Sexton
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Quote:
Originally Posted by amzamz View Post
Let us do this step by step: Assume we have rear tyres like "265 / 30 ZR 19". They have a circumference of 1.957m. There are 10 spokes on a Spyker wheel. To move one spoke into the position of the next one, we would need to travel a distance of 1/10 of the circumference. That is every 0.1957m. If the frame rate of the video is 25 frames per second (and I am not sure it is), that gives 0.04s frame to frame.

The condition to "stand still" would be given by 0.1957/0.04 = 4.89 m/s or multiples thereof. That means, we should be able to observe several "stand stills" during the acceleration of a Spyker, namely at 17.6, 35.2, 52.8, 70.5, 88.1, 105.7, 123.3, 140.9, 158.5, 176.1, 193.7 or 211.4 km/h etc.
I got about halfway through this and my head started to hurt!
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  #43 (permalink)  
Old 13-06-2010, 02:52
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Full name: Fiona Easterby
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Originally Posted by amzamz View Post
... nice cuts, Fiona! At what speed do the Spyker wheels appear to stand still? This is a question for a mathematician! What is the frame rate on YouTube, Fiona? Why do the other cars not show that phenomenon?

It's done in the camera by using a very fast shutter speed, around 2000th or faster. You can see it on some of the other cars too and most notably on the helicopter rotor blades in the highlights video. I think the propellor spoke design of the Spyker wheels lends itself better to the effect than the other cars so it's more noticeable.
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  #44 (permalink)  
Old 13-06-2010, 02:55
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Oh and the frame rate was indeed 25 fps
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  #45 (permalink)  
Old 13-06-2010, 06:40
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Quote:
Originally Posted by Mattjs33 View Post
I got about halfway through this and my head started to hurt!
... don't worry. Exactly for that reason Spyker made the C8! It is much easier to handle than math, and a lot of fun, too!
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